NapkinCalc

Electricity 1 — DC Circuits

Series & parallel

continues from lesson 1 — values defined earlier in the course stay live here

ELI5: resistors in series sit end-to-end, so the current fights through both — resistances add up. Resistors in parallel give the current two paths at once, so the combined resistance is smaller than either branch (more lanes = easier flow).

R2:=100ohmR_{2} := 100 ohm = 100 ohm
R3:=220ohmR_{3} := 220 ohm = 220 ohm
Rser=R2+R3R_{ser} = R_{2} + R_{3} = 320 ohm in series — they add
Rpar=11R2+1R3R_{par} = \frac{1}{\frac{1}{R_{2}} + \frac{1}{R_{3}}} = 68.75 ohm in parallel — smaller than R₂!
✓ pass Rpar<R2R_{par} < R_{2} parallel always beats the smallest branch

Real-world hook: series vs parallel is why old Christmas lights all died when one bulb failed (series) but your house outlets keep working independently (parallel).

Try it yourself: two 100 Ω resistors in parallel — what is the combined resistance?

Ryou:=1/(1/(100ohm)+1/(100ohm))R_{you} := 1 / (1/(100 ohm) + 1/(100 ohm)) = 50 ohm ✏️ Your turn: use 1/(1/R + 1/R) for two 100 Ω in parallel. (Two equal resistors in parallel halve.)
✓ pass abs(Ryou1/(1/(100ohm)+1/(100ohm)))<0.01ohmabs(R_{you} - 1 / (1/(100 ohm) + 1/(100 ohm))) < 0.01 ohm green when your parallel resistance is correct