NapkinCalc

Statics — Forces & Equilibrium

Friction — will it slide?

continues from lesson 5 — values defined earlier in the course stay live here

ELI5: friction resists sliding up to a limit, f_max = μ·N, where N is how hard the surfaces press together. Push below that limit and nothing budges; exceed it and the object breaks free. It's a threshold, not a fixed force.

gacc:=9.81m/s2g_{acc} := 9.81 m/s^2 = 9.81 m / s^2 gravity
mcrate:=50kgm_{crate} := 50 kg = 50 kg a crate on the floor
Nnormal=mcrategaccN_{normal} = m_{crate} \cdot g_{acc} = 490.5 (kg m) / s^2 the floor pushes back with this
μs=0.4\mu_{s} = 0.4 static friction coefficient (rubber on concrete-ish)
fmax=μsNnormalf_{max} = \mu_{s} \cdot N_{normal} = 196.2 (kg m) / s^2 the most friction available ≈ 196 N
Fshove:=150NF_{shove} := 150 N = 150 N how hard you push
✓ pass Fshove<fmaxF_{shove} < f_{max} TRUE → the crate stays put (push harder than 196 N to move it)

Real-world hook: μ·N is why car brakes have a limit (skidding), why bolted joints hold by clamping, and how a conveyor grips its load.

Try it yourself: the maximum friction on an 80 kg crate with μ = 0.3? (f = μ·m·g, use g = 9.81 m/s².)

fmaxyou:=0.380kg9.81m/s2fmax_{you} := 0.3 * 80 kg * 9.81 m/s^2 = 235.44 N ✏️ Your turn: multiply μ = 0.3 by the weight (80 kg × 9.81 m/s²).
✓ pass abs(fmaxyou0.380kg9.81m/s2)<0.01Nabs(fmax_{you} - 0.3 * 80 kg * 9.81 m/s^2) < 0.01 N green when your maximum friction force is correct

Where next: Mechanics of Materials takes these forces inside the material — turning a load into the stress that decides whether a part survives.