NapkinCalc

Physics 3 — Electricity & Magnetism

Magnetic force — only on the moving

continues from lesson 2 — values defined earlier in the course stay live here

A magnetic field does nothing to a parked charge. Move, and it pushes sideways — perpendicular to both v and B: F = q·v·B. Sideways force means circles, which is how mass spectrometers and old TVs steer beams:

qp=1.61019q_{p} = 1.6 \cdot 10^{-19} one proton (C)
vp=2000000v_{p} = 2000000 speed (m/s)
B1=0.5B_{1} = 0.5 field (T) — a strong lab magnet
Fm=qpvpB1F_{m} = q_{p} \cdot v_{p} \cdot B_{1} = 1.6×10131.6 \times 10^{-13} sideways force (N)
rcirc=1.671027vpqpB1r_{circ} = \frac{1.67 \cdot 10^{-27} \cdot v_{p}}{q_{p} \cdot B_{1}} = 0.04180.0418 radius of the proton's circle (m): r = mv/qB