NapkinCalc

Physics 1 — Motion & Energy

Free fall

continues from lesson 1 — values defined earlier in the course stay live here

Drop something: gravity supplies a constant acceleration g ≈ 9.81 m/s², so the same equations apply with v₀ = 0. Note the fall time grows with the SQUARE ROOT of height — four times higher only doubles the time.

g:=9.81m/s2g := 9.81 m/s^2 = 9.81 m / s^2 gravitational acceleration
h0:=45mh_{0} := 45 m = 45 m drop height
tfall:=sqrt(2h0/g)t_{fall} := sqrt(2 * h_{0} / g) = 3.0289 s time to hit the ground
vimpact:=gtfallv_{impact} := g * t_{fall} = 29.714 m / s impact speed