Fluid Mechanics — Flow & Pressure

Buoyancy — why steel ships float

continues from lesson 1 — values defined earlier in the course stay live here

ELI5: a submerged object is pushed up by the weight of the fluid it displaces: F = ρ·g·V. Displace more water-weight than you weigh, and you float — which is how a hull of dense steel stays on top.

V_{sub} := 0.05 m^3

= 0.05 m^3 submerged volume

F_{buoy} = \rho_{water} \cdot g_{acc} \cdot V_{sub}

= 490.5 (kg m m^3) / (m^3 s^2) upward buoyant force ≈ 491 N

✓ pass

abs(F_{buoy} - 490.5 N) < 0.5 N

the weight of the displaced water